Factorise 6x^2 + 11x + 4​

The factors of given polynomial are (2x + 1)(3x + 4). The given polynomial is 6x² + 11x + 4​. What is factorization? The factorization method uses basic factorization formula to reduce any algebraic or quadratic equation into its simpler form, where the equations are represented as the product of factors instead of expanding the brackets. The factors of any equation can be an integer, a variable, or an algebraic expression itself. Using the splitting middle term method, we get 6x² + 11x + 4 ⇒ 6x² + 8x + 3x + 4 ⇒ 2x(3x + 4)+1(3x + 4) ⇒ (2x + 1)(3x + 4) Therefore, the factors of given polynomial are (2x + 1)(3x + 4). To learn more about the factorization visit: brainly.com/question/26923098. #SPJ2

Answer: Step-by-step explanation: 6x^2+11x +4 Multiply the constant 4 by 6x^2. Hence 4 times 6x^2 = 24x^2 Get two numbers when you multiply them it will give you 24 but if you add them it will give 11. The numbers are +8 and +3 because +8 x +3= +24 and +8 + 3 = 11. Substituting +8x +3x as 11x in the equation: 6x^2 +8x +3x +4 (6x^2+ 8x) + (3x + 4) Factorizing the common things in the bracket. 2x(3x + 4) +1 (3x +4) since the common factor between (3x + 4) is 1. Grouping the values outside together: (2x+1) (3x +4) =0 Therefore, 2x + 1 = 0 or 3x +4 = 0 2x = -1 or 3x = -4 x = -1/2 or -4/3. Thanks.