Lucy and Zaki each throw a ball at atarget. 0.4 0.6 Lucy's throw Hit Miss 0.2 0.8 0.2 0.8 Zaki's throw Hit Miss Hit Miss What is the probability that both Lucy and Zaki hit the target?

we can conclude that Probability of both Lucy and Zaki hitting the target is 0.4. According to the statement we have to find the probability that the both Lucy and Zaki hit the target. So, For this purpose, we know that the Probability is the ratio of the number of outcomes in an exhaustive set of equally likely outcomes that produce a given event to the total number of possible outcomes. So, From the given information: When Zaki or Lucy throw a ball at the target there are only two outcomes for each of them ( i.e Hit or miss ) Therefore : The probability of Lucy hitting the target = 0.4/2 And The probability of Zaki hitting the target = 0.2+0.2/2 So, The Probability of both Lucy and Zaki hitting the target is: P(Lucy ) + P(Zaki ) = 0.4/2 + 0.4/2 P(Lucy ) + P(Zaki ) = 0.8/2 P(Lucy ) + P(Zaki ) = 0.4 Hence, we can conclude that Probability of both Lucy and Zaki hitting the target is 0.4. Learn more about Probability here brainly.com/question/24756209 #SPJ9

Final answer: The probability of both Lucy and Zaki hitting the target is calculated by multiplying the individual probabilities together, which gives us 0.08 or 8%. Explanation: The subject of this question is probability, a topic in mathematics. Specifically, we're being asked to calculate the probability that both Lucy and Zaki hit the target. The question provides us with the probability of Lucy hitting and missing the target, and the same for Zaki. Lucy hitting the target is 0.4, and Zaki hitting the target is 0.2. Probability events are independent, we multiply them to get the probability of both happening. Therefore, the probability of both Lucy and Zaki hitting the target is 0.4 * 0.2 = 0.08, or 8%. Learn more about Probability here: brainly.com/question/22962752 #SPJ3