a community hall is in the shape of a cuboid. the hall is 20m long, 15m wide and 4m high. the community hall needs re-decorating with new paint for the walls and ceiling, and new tiles on the floor. a 20l tin of paint covers 40 squared metres and costs £15. 1 squared metre floor tiles cost £3 each. work out the total cost of paint and tiles needed to decorate the community hall.

Final answer: The total cost for paint and tiles needed to decorate the community hall is £1125, with £225 for paint and £900 for tiles. Explanation: Calculating the Total Cost of Paint and Tiles for the Community Hall To calculate the total cost of paint and tiles needed for the community hall, we need to determine the total area to be painted and tiled. First, let's calculate the surface area to be painted, which includes the walls and the ceiling but not the floor since it will be tiled. The area of the four walls can be found by calculating the perimeter of the floor plan and multiplying it by the height of the hall. The perimeter of the rectangle is 2(20m + 15m) = 70m. Multiplying this by the height (4m) gives us the area of the walls: 70m * 4m = 280m². The area of the ceiling is simply the length times the width: 20m * 15m = 300m². Now, let's add the area of the walls and the ceiling to find the total area to be painted: 280m² (walls) + 300m² (ceiling) = 580m². A 20L tin of paint covers 40m², so we need 580m² / 40m² = 14.5 tins of paint. Since we cannot buy half a tin, we round up to 15 tins. The cost for the paint is therefore 15 tins * £15 per tin = £225. For tiling the floor, the area is the same as the ceiling which is 300m². The cost for tiling is therefore 300m² * £3 per m² = £900. Adding the cost for paint and tiles gives us the total cost: £225 (paint) + £900 (tiles) = £1125.

Answer: the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005. Step-by-step explanation: Area of the walls: - The community hall is shaped like a cuboid, so the walls are the four rectangular sides. - The length and height of each wall are given as 20m and 4m, respectively. - The total area of the walls is the sum of the areas of all four walls: 2 * (length * height + width * height). - Substituting the given values, we have: 2 * (20m * 4m + 15m * 4m). 2. Area of the ceiling: - The ceiling is also a rectangle, with the same length and width as the floor. - The area of the ceiling is given by length * width: 20m * 15m. 3. Area of the floor: - The area of the floor is the same as the area of the ceiling: 20m * 15m. Now, let's calculate the areas: 1. Area of the walls: - 2 * (20m * 4m + 15m * 4m) = 2 * (80m^2 + 60m^2) = 2 * 140m^2 = 280m^2. 2. Area of the ceiling: - 20m * 15m = 300m^2. 3. Area of the floor: - 20m * 15m = 300m^2. Next, we can calculate the number of tins of paint and tiles needed and their costs: - Number of tins of paint needed = Area of walls / Coverage per tin = 280m^2 / 40m^2/tin = 7 tins. - Cost of paint = Number of tins * Cost per tin = 7 tins * £15/tin = £105. - Number of tiles needed = Area of floor / Area per tile = 300m^2 / 1m^2/tile = 300 tiles. - Cost of tiles = Number of tiles * Cost per tile = 300 tiles * £3/tile = £900. Therefore, the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005. yes, i am a student