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Instrument MI-03-102 · Physics

Crossover Calculator

One resistor's worth of speaker, one capacitor, one frequency where a passive filter stops passing signal freely and starts cutting it — that's the corner this sheet finds.

Instrument MI-03-102
Sheet 1 OF 1
Rev A
Verified
Type 03 — Audio Electronics SER. 2026-03102

Crossover frequency

1,989.436789 Hz

f_c = 1 ⁄ (2πRC)

The working Every figure verified twice
  1. fc = 1 ⁄ (2·π·8·0.00001) = 1,989.436789
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How this instrument works

A first-order crossover built from a single capacitor is the simplest filter that still deserves the name: wire the capacitor in series ahead of a driver and its reactance, 1 ⁄ (2πfC), falls as frequency climbs. Below some frequency that reactance dominates and blocks most of the signal; above it, reactance has dropped low enough that the driver's own impedance dominates instead and signal passes through largely unimpeded. The corner between those two regimes — where reactance and resistance are exactly equal — is f_c = 1 ⁄ (2πRC), the point conventionally taken as the filter's edge, because it is where output power has fallen to half.

R in that formula is not a component you add on purpose; it's the loudspeaker's own nominal impedance, the 4, 6 or 8 Ω printed on its frame, standing in for the resistive half of the network. That substitution is what makes a one-part crossover possible at all — a tweeter, treated as a fixed resistor, is the second half of the RC pair whether or not anyone plans it that way. It's also the formula's weakest assumption: real voice coils are inductive, so a driver's true impedance rises with frequency rather than sitting still, which is why nominal-impedance calculations get closer to right near the crossover point and further off well above it.

One capacitor alone rolls off gently, at 6 dB per octave — a first-order slope, the gentlest a filter can have. Halve the frequency below f_c and only half the power disappears each time, not all of it, so a driver rated to handle midrange can still receive real energy an octave or more below the nominal corner. That gentleness is exactly why car-audio installers reach for this exact circuit as quick tweeter protection, and exactly why serious multi-way loudspeaker designs add a second component — typically a series inductor feeding the woofer — to steepen the split and keep bass fully off a driver never built to move it.

fc=12πRCf_c = \frac{1}{2\pi R C}XC(fc)=RX_C(f_c) = Rωc=1RC,fc=ωc2π\omega_c = \frac{1}{RC},\quad f_c = \frac{\omega_c}{2\pi}
f_c — crossover (corner) frequency, hertz (Hz) · R — resistance, ohms (Ω), typically the driver's nominal impedance · C — capacitance, farads (F) · X_C — capacitive reactance, ohms (Ω) · ω_c — angular corner frequency, radians per second (rad/s). At f_c, output power has fallen 3 dB (voltage to about 70.7%) and phase has shifted 45°.
  • Enter Resistance — usually the driver's nominal impedance in ohms (4, 6 or 8 Ω are the common values), or an actual series resistor if you're testing a true two-part network on a bench.
  • Enter Capacitance in the unit printed on the part: nF, µF or mF. Car-audio tweeter-protection capacitors typically run a few µF to a few tens of µF.
  • Read Crossover frequency in Hz, or switch to kHz for tweeter work — this is the -3 dB corner where roll-off has already begun, not a hard on/off line.
  • Try doubling Capacitance and watch Crossover frequency halve, then try halving Resistance instead and watch it double — both variables move the corner the same way.

Worked example — an 8 Ω tweeter behind a 10 µF capacitor

An 8 Ω tweeter is wired in series with a single 10 µF capacitor, the classic one-part high-pass crossover fitted ahead of countless car-door tweeters. Enter 8 into Resistance and 10 (µF) into Capacitance: f_c = 1 ⁄ (2π × 8 × 0.00001) = 1,989.4 Hz. Above roughly 2 kHz the tweeter receives signal close to full strength; below it, output rolls away at 6 dB per octave rather than cutting off sharply.

Swap that part for a 20 µF capacitor and the corner drops to 994.7 Hz — a larger capacitor has lower reactance at any given frequency, so it takes a lower frequency to bring that reactance back up to 8 Ω, letting more midrange reach a tweeter that likely doesn't want it. Fit a 4 Ω tweeter instead, keeping the original 10 µF capacitor, and the corner rises to 3,978.9 Hz, because halving R has exactly the same doubling effect on f_c that halving C does — both sit in the same denominator.

Questions

Why does this formula use the speaker's impedance as the resistance?

Because a one-capacitor crossover has only one other component in the circuit: the driver itself. Its nominal impedance — 4, 6 or 8 Ω, printed on the frame or in the datasheet — stands in for R, so the tweeter is simultaneously the load and half the filter. That's a simplification, since a voice coil's real impedance rises with frequency rather than staying fixed, but it's accurate enough near the crossover point for practical tweeter protection.

What does the -3 dB corner actually mean?

At f_c, output voltage has fallen to about 70.7% of its full-passband value — half the power, in decibel terms exactly -3 dB. It isn't a wall between 'passing' and 'blocked'; signal an octave above f_c is already near full strength, and signal an octave below still carries roughly a quarter of the power, because a first-order filter rolls off gradually rather than snapping shut.

Is one capacitor enough to fully protect a tweeter?

Rarely completely. A single-capacitor filter is first-order, rolling off at only 6 dB per octave — the gentlest slope a filter can have — so meaningful midrange and even some bass energy still reach the driver an octave or more below f_c. Full protection against loud bass usually needs a steeper, higher-order network; the single capacitor is a fast, cheap partial measure, common in car audio precisely because it's fast and cheap.

Why does doubling the capacitance halve the crossover frequency?

Because capacitance sits in the denominator of f_c = 1 ⁄ (2πRC) exactly as resistance does. Doubling C halves reactance at every frequency, so a lower frequency is now needed to bring that reactance back up to match R. With an 8 Ω tweeter, 10 µF gives 1,989.4 Hz and 20 µF gives 994.7 Hz — precisely half, matching the inverse relationship the formula predicts.

Does this same formula work for a low-pass filter to a woofer?

The corner-frequency arithmetic is identical, but the circuit isn't: a high-pass crossover puts the capacitor in series ahead of the tweeter, while a low-pass crossover typically puts an inductor in series ahead of the woofer instead, or a capacitor in shunt across it. This sheet computes the RC, capacitor-only case; a series-inductor woofer filter needs L in place of C in the same 1 ⁄ (2πRX) shape.

Why might a real crossover measure differently from this result?

Because nominal impedance is an approximation, not a measurement. A voice coil's inductance raises true impedance above the nominal figure as frequency climbs, and mechanical resonance near a driver's free-air resonant frequency adds a peak of its own. Treating impedance as one fixed R gets the corner roughly right for quick tweeter protection, but a precisely tuned multi-way crossover is designed against the driver's actual measured impedance curve, not its nameplate value.

References