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Instrument MI-03-117 · Physics

DC Wire Size Calculator

Two conductors carry every DC amp you send out, supply and return alike, so this sizes copper against the full loop length rather than a one-way figure and a hidden multiplier.

Instrument MI-03-117
Sheet 1 OF 1
Rev A
Verified
Type 03 — Electrical SER. 2026-03117

Minimum wire size, circular mils

16,125.000000

VD = V × drop%

0.360000 Allowed voltage drop (V)
The working Every figure verified twice
  1. allowedDropVolts = 12·3 ⁄ 100 = 0.360000
  2. circularMils = 12.9·15·30 ⁄ 0.36 = 16,125.000000
Worksheet log
  1. No entries yet — change an input to log a scenario.

How this instrument works

A circular mil is simply area, kept free of pi: take a wire one mil across — a mil being one thousandth of an inch — and its cross-section, in circular mils, is that diameter-in-mils number squared. American gauge tables are built on this unit because area, not diameter, is what governs how much resistance a given length of copper actually has, so a wire's circular-mil rating is the one figure this calculator's result can be compared against directly, without converting anything first.

Both quantities this formula multiplies together are already loop quantities, because a two-wire DC circuit has no shortcut the way some AC wiring does. Current travels out through one conductor and comes back through the other, and both legs are equally ordinary copper carrying equally ordinary resistance — nothing here plays the role a shared neutral sometimes plays in AC wiring. That is why Round-trip wire length asks for the full there-and-back distance directly rather than a one-way number the formula would otherwise have to double behind the scenes: measuring the loop once, tape out and tape back, removes a step where a factor of two could quietly go missing or get applied twice. K, the 12.9 figure standing in for copper here, runs a touch above copper's cool-bench resistivity on purpose, covering a stranded conductor that will run warmer than a lab sample once it is loaded, bundled and left in the sun.

Twelve volts nominal is rarely twelve volts under load. A lead-acid bank sags toward 11.5 to 11.8 V well before it reads empty, and a lithium pack can slide from 13.2 V resting down past 12.0 V mid-discharge, so a drop budget figured against a tidy 12.0 V input is really a budget against whatever the source happens to read at the moment the load switches on. Anyone sizing a circuit that has to keep working near the bottom of a discharge curve — a bilge pump, an alarm system, an inverter feed — does better entering the lowest voltage the source will realistically show rather than its nameplate figure, since a conductor that clears a 3 percent budget at 12.6 V can fail that same test at 11.5 V.

VD=V×drop%100VD = \frac{V \times \text{drop\%}}{100}CM=K×I×LrtVDCM = \frac{K \times I \times L_{rt}}{VD}
VD — allowed voltage drop, in volts (V) · V — system voltage (V) · drop% — allowed drop as a percentage of V · K — circular-mil-ohms per foot for copper, 12.9 · I — circuit current, in amperes (A) · L_rt — round-trip conductor length, in feet (ft) · CM — minimum conductor area, in circular mils.
  • Enter Circuit current — the steady DC amps the load actually draws, separate from any breaker or fuse trip rating.
  • Enter Round-trip wire length (there and back) — measure the full loop, supply conductor and return conductor together, in one figure.
  • Set System voltage to the battery or supply rail feeding the circuit — 12 V, 24 V and 48 V are the common DC rails.
  • Set Allowed voltage drop, % to the fraction of that voltage you can spend in the wire — 2 to 3 percent suits sensitive electronics, a little more is tolerable for lighting or heating loads.
  • Read Allowed voltage drop in volts and Minimum wire size, circular mils — the smallest standard wire gauge above that figure is the one to buy, not the one below it.

Worked example — a 15 A solar charge-controller run

A rooftop panel feeds a charge controller 15 feet away, so the positive and negative conductors together make a 30 ft round trip. The array can push 15 A, the system runs at 12 V, and the installer wants no more than a 3 percent drop. First VD = 12 × 3 ⁄ 100 = 0.36 V — barely a third of a volt to spend across the whole loop. Then CM = 12.9 × 15 × 30 ⁄ 0.36 = 5,805 ⁄ 0.36 = 16,125 circular mils.

That figure lands just under 8 AWG's 16,510 circular-mil rating and comfortably clear of 10 AWG's 10,380, so 8 AWG copper is the smallest stock size that satisfies the budget. Because this particular run lives outdoors between a roof and an enclosure, many installers reach for tinned marine-grade cable at that same 8 AWG size rather than plain building wire — the copper cross-section and the arithmetic above stay identical either way, but the tin plating resists the corrosion that weather works into a crimped ring terminal, which is usually where a marginal outdoor connection fails first, well before the conductor itself would.

Questions

What is a circular mil, and how does it relate to a square one?

Picture a circle one mil across: its enclosed area, by definition, is one circular mil, while a square with a one-mil side is one square mil. A circle inscribed in a square fills about 78.5 percent of it, so a circular mil equals pi over 4 square mils, roughly 0.785 of one, or about 5.067 x 10⁻⁴ mm² in metric terms.

Why does this ask for round-trip length instead of a one-way distance?

Because a two-wire DC circuit has no leg that gets to skip resistance. Current flows out on one conductor and back on the other, so both add to the total, and asking for the loop distance directly avoids the common slip of entering a one-way figure and forgetting a doubling step, or applying that doubling twice by mistake.

Should I enter 12.0 V nominal, or the battery's actual resting voltage?

For a circuit that must keep working near the end of a discharge cycle, enter the lowest voltage the source will realistically show, not its nameplate figure. A lead-acid bank can sag to 11.5 V under load well before it reads empty, and a drop budget calculated against a full 12.6 V does not describe the wire's behavior once the battery has actually been drawn down.

Does an outdoor or marine DC run need anything beyond the right circular-mil size?

The copper area math stays the same, but the conductor construction often does not. Runs exposed to weather commonly use tinned stranded marine cable rather than plain building wire at the identical AWG size, because the tin plating resists corrosion at crimped terminals — usually the first place a marginal outdoor connection actually fails, ahead of the wire itself.

If I raise the allowed voltage drop percentage, does the required wire shrink?

Yes. VD grows with drop percent, and circular mils fall as VD grows, so a looser budget lowers the minimum conductor size. Raising the worked example's allowance from 3 to 5 percent lifts VD to 0.6 V and drops the requirement to 9,675 circular mils, small enough for 10 AWG — at the cost of a dimmer or slower-charging load at the far end of the wire.

Is sizing by voltage drop the same as sizing by ampacity?

No, and the two can disagree. Ampacity tables size a conductor so it does not overheat carrying a given current, independent of how far it runs; this formula sizes it so voltage lost along that specific length stays within budget. Short high-current runs are usually ampacity-limited, long low-voltage runs are usually drop-limited, and the wire you should actually buy is whichever calculation asks for more copper.

References