SOLVETUTORMATH SOLVER

Instrument MI-01-276 · Mathematics

Hexagonal Pyramid Calculator

A hexagonal pyramid's exterior has seven faces: one hexagonal base and six triangular sides. Enter the edge and slant height, and this sheet returns all three areas.

Instrument MI-01-276
Sheet 1 OF 1
Rev A
Verified
Type 05 — Geometry SER. 2026-01276

Total surface area

113.56921938

base area = (3√3⁄2)s²

41.56921938 Base area
72.00000000 Lateral (side) area
The working Every figure verified twice
  1. baseArea = 3·√(3) ⁄ 2·4^2 = 41.56921938
  2. lateralArea = 3·4·6 = 72.00000000
  3. area = 3·√(3) ⁄ 2·4^2 + 3·4·6 = 113.56921938
Worksheet log
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How this instrument works

A hexagonal pyramid has a regular hexagonal base and six triangular faces rising to meet at a single apex above it. Its total surface area comes from two separate pieces added together: the base's own hexagon area, (3√3⁄2)s², and the combined area of all six triangular side faces, each with area ½·s·slant, giving 3·s·slant once all six identical triangles are summed.

This is a genuinely different calculation from this site's Hexagonal Pyramid Volume page, even though both start from the same hexagonal base. Volume needs the pyramid's perpendicular HEIGHT (straight up from the base's center to the apex), while surface area needs the SLANT height instead (the distance from the apex down to the midpoint of one base edge, measured along a triangular face) — two different lengths describing the same solid from different angles, and mixing them up is a common source of error.

The slant height and the perpendicular height are related through the Pythagorean theorem via the hexagon's own apothem (the distance from its center to the midpoint of a side): slant² = height² + apothem², so if only the perpendicular height is known, the slant height can still be recovered before this calculator's formulas are applied.

Abase=332s2A_{\text{base}} = \frac{3\sqrt{3}}{2}s^2Alateral=3sslantA_{\text{lateral}} = 3\,s\cdot\text{slant}Atotal=Abase+AlateralA_{\text{total}} = A_{\text{base}} + A_{\text{lateral}}
s — the hexagonal base's edge length; slant — the slant height, apex to a base edge's midpoint; total — the pyramid's complete exterior surface area.
  • Enter the regular hexagonal base's edge length into the Base edge length field.
  • Enter the slant height (apex to a base edge's midpoint, along a triangular face) into the Slant height field.
  • Read Base area, Lateral (side) area, and Total surface area: the sheet computes all three simultaneously.

Worked example — base edge 4, slant height 6

A hexagonal pyramid has a base edge of 4 and a slant height of 6. Its base area is (3√3⁄2) × 16 ≈ 41.57, its lateral area is 3 × 4 × 6 = 72 (six triangular faces, each ½×4×6=12, combined), and its total surface area is about 113.57 — the base and the six slanted sides added together for the complete exterior.

A smaller base with edge 2 and a taller slant height of 9 has base area about 10.39, lateral area 3×2×9=54, and total area about 64.39 — a narrower base compensated by a steeper, taller slant, reaching a comparable total exterior through very different proportions.

Questions

What is the formula for a hexagonal pyramid's surface area?

Total surface area = (3√3⁄2)s² + 3·s·slant, combining the regular hexagonal base's own area with the combined area of the six identical triangular side faces, each computed from the base edge s and the slant height.

What is slant height versus perpendicular height?

The perpendicular height runs straight up from the base's center to the apex; the slant height instead runs from the apex down to the midpoint of one base edge, measured along a triangular face. Surface area needs the slant height; volume needs the perpendicular height — they are NOT interchangeable.

How is this different from the hexagonal pyramid volume page?

That page finds the enclosed VOLUME from the base edge and the perpendicular height. This page instead finds the total exterior SURFACE AREA from the base edge and the slant height — two related but genuinely different questions about the same solid.

Can I convert perpendicular height to slant height?

Yes — using the Pythagorean theorem with the hexagon's apothem (the distance from its center to a side's midpoint): slant² = height² + apothem². If only the perpendicular height is known, this relationship recovers the slant height needed for the surface area formulas here.

What if the base edge is zero?

The entire pyramid collapses to a single point, and every area — base, lateral, and total — comes out to exactly zero, regardless of the slant height entered.

References