How many grams of sodium bicarbonate are in 200 mL of 8.4% sodium bicarbonate?

The mass of sodium bicarbonate in 200 mL of an 8.4% solution is 16.8 grams. To calculate the mass of sodium bicarbonate in the solution, we can use the formula: Given: - The volume of the solution is 200 mL. - The concentration of sodium bicarbonate in the solution is 8.4%. First, we need to convert the volume from milliliters to liters because the concentration is given in percentage by volume, which is compatible with liters. Now, we can calculate the mass of sodium bicarbonate: Since 1% is equivalent to 0.01 in decimal form, we can express 8.4% as 0.084. To convert kilograms to grams, we multiply by 1000:

Final answer: To find the number of grams of sodium bicarbonate in 200 mL of an 8.4% solution, multiply 200 mL by the percentage concentration (as a decimal). The calculation yields 16.8 grams of sodium bicarbonate. Explanation: To calculate the amount of sodium bicarbonate in 200 mL of an 8.4% solution, you can follow these steps: First, understand the percentage concentration implies that 8.4 grams of sodium bicarbonate are present in every 100 mL of the solution. Next, calculate how many grams are in 200 mL by setting up a proportion or simply doubling the amount from the 100 mL proportion because 200 mL is twice as much as 100 mL. To find the mass of the sodium bicarbonate in 200 mL, you multiply the volume by the percentage (expressed as a decimal) and the density of the solution if it's different from water (for this problem, you can assume it's approximately the same as water, which is 1 g/mL). So, the calculation would be: 200 mL * 0.084 which equals 16.8 grams of sodium bicarbonate.