SOLVETUTORMATH SOLVER

Instrument MI-06-223 · Everyday life

Roll Length Calculator

Measure a roll's outer diameter, its core diameter and the material's thickness, and this calculator estimates how much length — in meters — is actually wound onto it, without unrolling a single centimeter.

Instrument MI-06-223
Sheet 1 OF 1
Rev A
Verified
Type 06 — Crafts & Hobbies SER. 2026-06223

Material length (m)

75.398

length = pi x (outer² − core²) / (4 x thickness)

The working Every figure verified twice
  1. lengthM = π·(220·220 − 20·20) ⁄ (4·0.5) ⁄ 1000 = 75.398
Worksheet log
  1. No entries yet — change an input to log a scenario.

How this instrument works

A wound roll of material — fabric, film, paper, tape, wire — is really a long strip curled into a tight spiral, and the cross-section of that spiral, viewed end-on, is an annulus: a ring shape, the area between the roll's outer circle and its inner core circle. The key geometric insight behind this calculator is that if you unrolled the material flat, it would form a long, thin rectangle whose area exactly equals that annulus's area — same amount of material, just described two different ways.

A rectangle's area is simply its length times its height, and here the 'height' of that unrolled rectangle is the material's thickness. So once you know the annulus's area (from the outer and core diameters, using the standard circle-area formula) and the material's thickness, dividing area by thickness gives you the unrolled length directly — no need to actually unspool the roll and measure it.

This is an estimate, not a guaranteed exact figure, because it assumes the roll is wound perfectly tight with no air gaps between layers and a perfectly uniform thickness throughout — real rolls, especially of flexible material like fabric or film, often wind slightly loosely or unevenly, which can make the true length differ modestly from this calculation. For most practical planning purposes (do I have enough tape left, roughly how much fabric is on this bolt) the estimate is close enough to be genuinely useful.

L=π(D2d2)4t×103L = \dfrac{\pi (D^2 - d^2)}{4t} \times 10^{-3}
D — outer roll diameter in mm. d — core (inner) diameter in mm. t — material thickness in mm. L — estimated unwound material length in meters. The formula equates the roll's cross-sectional annulus area, π(D²−d²)/4, to the area of the unrolled material as a long thin rectangle (length × thickness), then solves for length and converts millimeters to meters.
  • Measure the roll's Outer (roll) diameter (mm) — straight across the widest point, through the center.
  • Measure the Core (inner) diameter (mm) — the diameter of the empty tube or core the material is wound around.
  • Enter the Material thickness (mm) — how thick a single layer of the material is; check a spec sheet if you don't want to measure it directly.
  • Read Material length (m) for the estimated total length wound onto the roll.

Worked example — a roll of film, 220mm outer, 20mm core

A roll of packaging film measures 220 mm across the outside, is wound on a 20 mm core, and the film itself is 0.5 mm thick. Length = π × (220² − 20²) ÷ (4 × 0.5) ÷ 1000 = π × (48,400 − 400) ÷ 2 ÷ 1000 = π × 24 ≈ 75.40 meters.

That's a genuinely useful number to know before starting a job that needs a specific length of film — rather than guessing from the roll's weight or diameter alone, the calculation gives a concrete meter figure to plan against.

Questions

Why does this formula work without actually unrolling the material?

Because the roll's cross-section (viewed end-on) is a ring shape — an annulus — whose area is a simple function of the outer and inner diameters, and that same area exactly equals the area of the material laid out flat as a long rectangle (length times thickness). Since both descriptions have to have the same area, dividing the annulus area by the thickness gives the unrolled length directly, with no unspooling required.

How accurate is this estimate in practice?

It's an idealized estimate that assumes perfectly tight winding with no air gaps and a perfectly uniform thickness throughout — real-world rolls, especially of soft or flexible material, often wind slightly loosely, which can make the true length a bit shorter than the formula predicts. For firm, uniform materials like film or tape it tends to be quite close; for loosely wound fabric, treat it as a solid ballpark rather than an exact count.

What units does the calculator expect, and does that matter?

Outer diameter, core diameter and thickness are all entered in millimeters, and the result comes out in meters — the calculator handles that unit conversion internally, so there's no need to convert your caliper or ruler measurement yourself before entering it.

Can I use this for a roll of wire or cable instead of a flat material?

Not with this formula as written — it assumes the wound material is a flat strip of consistent thickness (film, paper, fabric, tape), where the unrolled cross-section is a simple rectangle. Wound wire or cable packs differently (round cross-sections nesting together rather than flat layers stacking), so it needs a different length-estimation approach.

What if I don't know the material's exact thickness?

Check a manufacturer's spec sheet first, since thickness is often listed precisely there; failing that, measure a small stack of several layers (or, for something like paper, use this site's Paper Thickness Calculator on a measured stack) and divide by the layer count for a more accurate figure than trying to measure one layer directly.

References