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Instrument MI-01-608 · Mathematics

Synthetic Division Calculator

Dividing a cubic by (x−r) collapses to three quick multiply-and-add steps. Enter the cubic's coefficients and r, and this sheet returns the quotient and remainder.

Instrument MI-01-608
Sheet 1 OF 1
Rev A
Verified
Type 05 — Algebra SER. 2026-01608

Remainder

0.00000000

q₂ = a

1.00000000 Quotient: x² coefficient
-5.00000000 Quotient: x coefficient
6.00000000 Quotient: constant term
The working Every figure verified twice
  1. q2 = 1 = 1.00000000
  2. q1 = -6 + 1·1 = -5.00000000
  3. q0 = 11 + (-6 + 1·1)·1 = 6.00000000
  4. remainder = -6 + (11 + (-6 + 1·1)·1)·1 = 0.00000000
Worksheet log
  1. No entries yet — change an input to log a scenario.

How this instrument works

Synthetic division is a streamlined shortcut for dividing a polynomial by a linear factor (x−r), skipping the more elaborate bookkeeping of full polynomial long division. For a cubic ax³+bx²+cx+d divided by (x−r), the process runs in three quick steps: the quotient's leading coefficient is simply a; the next coefficient is b plus a·r; the one after that is c plus the previous result times r; and whatever comes out at the very end is the remainder — d plus the prior result times r.

A remainder of exactly 0 carries real meaning: it confirms that r is a genuine root of the original cubic, since dividing evenly with nothing left over means (x−r) is an exact factor. This is exactly how the Factor Theorem gets applied in practice — testing candidate roots one at a time via synthetic division, with a zero remainder confirming a hit.

This page is scoped specifically to a cubic divided by a linear factor, the case where synthetic division's fixed, three-step pattern applies cleanly. Higher-degree polynomials extend the identical multiply-and-add pattern with more steps, and dividing by a non-linear factor needs full polynomial long division instead, since synthetic division's shortcut relies specifically on the divisor being of the simple form (x−r).

q2=a, q1=b+ar, q0=c+q1rq_2=a,\ q_1=b+ar,\ q_0=c+q_1 rremainder=d+q0r\text{remainder} = d+q_0 r
a, b, c, d — the cubic's coefficients; r — the root of the divisor (x−r); q₂, q₁, q₀ — the quotient's coefficients; remainder — what's left over.
  • Enter the cubic's four coefficients into the a, b, c, and d fields, from ax³+bx²+cx+d.
  • Enter the root of the linear divisor into the Divide by (x − r) field.
  • Read the quotient's three coefficients and the remainder: the sheet applies the three-step synthetic division process automatically.

Worked example — x³−6x²+11x−6 divided by (x−1)

Dividing x³−6x²+11x−6 by (x−1): q₂=1, q₁=−6+1×1=−5, q₀=11+(−5)×1=6, and remainder=−6+6×1=0 — the quotient is x²−5x+6, with a remainder of exactly 0, confirming x=1 is a genuine root of the original cubic.

Dividing 2x³+3x²−8x+3 by (x−2) instead gives quotient 2x²+7x+6 with a remainder of 15 — a nonzero remainder means x=2 is NOT a root of this particular cubic, the division simply doesn't come out even.

Questions

What is synthetic division?

A streamlined shortcut for dividing a polynomial by a linear factor (x−r), using a compact series of multiply-and-add steps instead of the more elaborate bookkeeping full polynomial long division requires.

What does a remainder of zero mean?

It confirms that r is a genuine root of the original polynomial — dividing evenly with nothing left over means (x−r) is an exact factor, the Factor Theorem's own defining condition.

Can synthetic division divide by anything other than (x−r)?

Not directly — this shortcut relies specifically on the divisor having that simple linear form. Dividing by a quadratic or higher-degree divisor needs full polynomial long division instead.

How is synthetic division used to find roots?

By testing candidate values of r one at a time — a zero remainder confirms a hit, identifying r as a genuine root, while a nonzero remainder rules that candidate out, a common technique alongside the Rational Root Theorem for narrowing down where a polynomial's roots might be.

Does this extend to polynomials of a higher degree than cubic?

Yes — the identical multiply-and-add pattern extends to any degree, simply with more coefficients and more steps; this page is scoped to the cubic case specifically as the most common starting point.

References