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Instrument MI-03-465 · Physics

Telescope Magnification Calculator

Swap eyepieces and the same tube goes from a wide, faint overview to a tight, bright close-up. Magnification is nothing more than two focal lengths, divided.

Instrument MI-03-465
Sheet 1 OF 1
Rev A
Verified
Type 03 — Optics SER. 2026-03465

Magnification, ×

100.000000

M = F_tele ⁄ F_eye

The working Every figure verified twice
  1. mag = 1 ⁄ 0.01 = 100.000000
Worksheet log
  1. No entries yet — change an input to log a scenario.

How this instrument works

Magnification tells you how many times larger an object's apparent angle grows once you look through the eyepiece instead of at the sky with a bare eye. A lunar crater that spans a barely visible sliver of the Moon's disc to the naked eye can fill a large fraction of the field of view at 100×. The objective lens or mirror does the first half of the work: it gathers light and bends it into a real, upside-down image sitting at its focal plane, a distance Ftele behind the glass. The eyepiece then behaves like an ordinary magnifying glass held right at that image, blowing it back up for the eye.

Both focal lengths decide the power because each one fixes an angle in the same short chain of triangles. A longer telescope focal length spreads a given patch of sky across a physically larger image at the focal plane — more millimetres of image for the same degrees of sky. A shorter eyepiece focal length then squeezes more magnifying power out of whatever image lands in front of it, the way a magnifying glass with a shorter focal length sits closer to the page and swells the print more. Divide one by the other, Ftele ⁄ Feye, and the eyepiece's barrel width, coatings, lens count, and advertised field of view all cancel out, because none of them change where the image forms or how large it already is.

The formula itself has no ceiling, but the sky does. An aperture collects a fixed cone of light, so cranking magnification only spreads that same light over a larger, dimmer disc at the eye — the exit pupil, aperture divided by magnification. Push past roughly twice the aperture in millimetres and the exit pupil shrinks below what a dark-adapted eye can use; the view dims, and any air turbulence or focus error gets magnified right along with the target. This is the trap behind department-store telescopes boasting numbers like '675× power': a 60 mm lens can print that ratio on the box using a tiny enough eyepiece, while the actual view stays a dim, shaking smear.

M=FteleFeyeM = \frac{F_{tele}}{F_{eye}}Exit pupil=DM\text{Exit pupil} = \frac{D}{M}
M — magnification, a dimensionless ratio expressed as ×. F_tele — telescope (objective) focal length. F_eye — eyepiece focal length, in the same unit as F_tele. D — aperture (objective) diameter, used only for the exit-pupil check, typically in millimetres.
  • Find the Telescope focal length, usually printed on the tube or in the manual — commonly 650 mm to 2,032 mm on amateur scopes, longer for many Cassegrains.
  • Find the Eyepiece focal length stamped near the top of the eyepiece barrel, typically somewhere between 3 mm and 32 mm.
  • Enter both in the same length unit and read Magnification, × — the ratio is unitless, so no conversion step is needed once the units match.
  • Re-enter a different Eyepiece focal length to compare eyepieces before buying one, or halve whichever eyepiece value you enter to model adding a 2× Barlow lens.

Worked example — a 1,000 mm scope with a 10 mm eyepiece

A common beginner telescope carries a Telescope focal length of 1,000 mm. Pair it with the 10 mm eyepiece that typically ships in the box: Magnification, × = 1,000 ⁄ 10 = 100×. At that power, Saturn's rings separate cleanly from its disc and Jupiter's four Galilean moons resolve into a tidy line, rather than the single featureless point either shows to the naked eye.

Swap in a shorter 5 mm eyepiece and the identical tube jumps to 1,000 ⁄ 5 = 200× — double the power from the same telescope, because focal length alone sets the ratio and eyepiece construction never enters the formula. That is exactly why amateur astronomers carry a small case of eyepieces rather than a telescope with one fixed magnification: changing the view means changing Feye, and nothing about the telescope itself has to move.

Questions

Why does eyepiece focal length matter more than eyepiece size?

Because magnification only cares about focal length, not barrel diameter or advertised field of view. Two eyepieces can share the same 31.7 mm barrel yet run anywhere from 4 mm to 40 mm in focal length — swapping between them changes power by a factor of ten, while the mechanical fitting stays identical. Apparent field of view changes how much sky is visible at once, not how large each object appears, which is set purely by Ftele ⁄ Feye.

Is there a maximum useful magnification for a given telescope?

Yes, roughly twice the aperture in millimetres, or about 50× per inch. Past that point the exit pupil — aperture divided by magnification — shrinks below what the eye can use, so the image only gets dimmer and softer, never sharper. A 114 mm reflector tops out near 228×; pushing to 400× with a tiny eyepiece just enlarges the same limited detail, plus every wobble of the air, into a bigger smear.

Does a shorter eyepiece always give a better view?

No. Higher magnification also brings a dimmer image, a narrower field of view, and shorter eye relief that is less comfortable to use. Extended targets such as nebulae and large galaxies often look better at low power, where more light lands per unit of retina; only small, bright objects — planets, the Moon, tight double stars — reward pushing toward the telescope's magnification ceiling.

How do I find my telescope's focal length if it isn't labeled?

Multiply the aperture diameter by the focal ratio, the 'f/number' printed on the tube or in the manual — an 80 mm f/11 refractor has a Telescope focal length of 80 × 11 = 880 mm. If neither figure is on hand, the manufacturer's spec sheet almost always lists it directly, since focal length is fixed by the optical design and never changes with whichever eyepiece is inserted.

What does a Barlow lens do to this calculation?

A 2× Barlow doubles the effective Telescope focal length before the ratio is taken, so entering 2,000 mm instead of 1,000 mm reproduces its effect exactly. A 10 mm eyepiece that gave 100× on its own now gives 200× with the Barlow in the light path — the identical result you would get by halving the eyepiece focal length instead.

Why do cheap telescopes advertise huge magnification numbers?

Because the arithmetic allows any figure at all — a tiny enough eyepiece focal length divided into any telescope focal length produces a large ratio on paper. A 60 mm department-store scope claiming '675×' is running an eyepiece far shorter than any exit pupil could actually use, so the resulting view is dim, unsteady, and no more detailed than a much lower power. Aperture, not the printed magnification claim, is what limits what a telescope can genuinely show.

References